(5y/y^2-3y)-(7/3-y)

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Solution for (5y/y^2-3y)-(7/3-y) equation:


D( y )

y^2 = 0

y^2 = 0

y^2 = 0

1*y^2 = 0 // : 1

y^2 = 0

y = 0

y in (-oo:0) U (0:+oo)

y-(3*y)+(5*y)/(y^2)-(7/3) = 0

y-3*y+(5*y)/(y^2)-7/3 = 0

5*y^-1-2*y^1-7/3*y^0 = 0

(5*y^0-2*y^2-7/3*y^1)/(y^1) = 0 // * y^2

y^1*(5*y^0-2*y^2-7/3*y^1) = 0

y^1

(-7/3)*y-2*y^2+5 = 0

(-7/3)*y-2*y^2+5 = 0

DELTA = (-7/3)^2-(-2*4*5)

DELTA = 409/9

DELTA > 0

y = ((409/9)^(1/2)-(-7/3))/(-2*2) or y = (-(-7/3)-(409/9)^(1/2))/(-2*2)

y = ((409/9)^(1/2)+7/3)/(-4) or y = (7/3-(409/9)^(1/2))/(-4)

y in { ((409/9)^(1/2)+7/3)/(-4), (7/3-(409/9)^(1/2))/(-4)}

y in { ((409/9)^(1/2)+7/3)/(-4), (7/3-(409/9)^(1/2))/(-4) }

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